(4x^2+34x+44)/(x+7)

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Solution for (4x^2+34x+44)/(x+7) equation:


D( x )

x+7 = 0

x+7 = 0

x+7 = 0

x+7 = 0 // - 7

x = -7

x in (-oo:-7) U (-7:+oo)

(4*x^2+34*x+44)/(x+7) = 0

4*x^2+34*x+44 = 0

2*(2*x^2+17*x+22) = 0

2*x^2+17*x+22 = 0

DELTA = 17^2-(2*4*22)

DELTA = 113

DELTA > 0

x = (113^(1/2)-17)/(2*2) or x = (-113^(1/2)-17)/(2*2)

x = (113^(1/2)-17)/4 or x = (-(113^(1/2)+17))/4

2*(x+(113^(1/2)+17)/4)*(x-((113^(1/2)-17)/4)) = 0

(2*(x+(113^(1/2)+17)/4)*(x-((113^(1/2)-17)/4)))/(x+7) = 0

( x+(113^(1/2)+17)/4 )

x+(113^(1/2)+17)/4 = 0 // - (113^(1/2)+17)/4

x = -((113^(1/2)+17)/4)

( x-((113^(1/2)-17)/4) )

x-((113^(1/2)-17)/4) = 0 // + (113^(1/2)-17)/4

x = (113^(1/2)-17)/4

x in { -((113^(1/2)+17)/4), (113^(1/2)-17)/4 }

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